Verified answer

Объяснение:

[tex]\left \{ {{\frac{1-3x}{4}-\frac{4-2p}{3}=0\ |*12 } \atop {0,7=0,4p-0,3x\ |*10}} \right.\ \ \ \ \left \{ {{3*(1-3x)-4*(4-2p)=0} \atop {7=4p-3x}} \right. \ \ \ \ \left \{ {{3-9x-16+8p=0} \atop {4p-3x=7}} \right. \ \ \ \ \ \left \{ {{8p-9x=13} \atop {4p-3x=7}} \right. \ \ \ \\[/tex]

[tex]\left \{ {{2*4p-9x=13} \atop {4p=3x+7\ |:4}} \right. \ \ \ \ \ \left \{ {{2*(3x+7)-9x=13} \atop {4p=3x+7} \right. \ \ \ \ \ \left \{ {{6x+14-9x=13} \atop {p=\frac{3x+7}{4} }} \right.\ \ \ \ \left \{ {{3x=1\ |:3} \atop {p=\frac{3x+7}{4} }} \right.\ \ \ \ \left \{ {{x=\frac{1}{3} } \atop {p=2}} \right. .[/tex]

Ответ: x=1/3    p=2.

Ответ:

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