Verified answer

[tex]\frac{3x+2}{2} +\frac{5-2x}{3} =6\\\\3(3x+2)+2(5-2x)=36\\9x+6+10-4x=36\\9x+16-4x=36\\5x+16=36\\5x=36-16\\5x=20\\x=20 :5\\x=4\\\\\frac{3*4+2}{2} +\frac{5-2*4}{3} \\\frac{12+2}{2} +\frac{5-8}{3}\\\frac{14}{2} +\frac{-3}{3}\\7-1 = 6[/tex]