Ответ:
1)х^4-9=(х²-3)(х²+3)
4х²-9=0; (2х-3)(2х+3)
(63-27)(63+27)/(83-79)(83+79)=36•100/4•162=50/9=5 5/9
4) -(27b^6+1)= -(3b²+1)(9b^4-3b+1)
5) (mn-1)(m²n²+mn+1)
16x²-9-16x²+2x=0
2x=9; x=4,5
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Verified answer
Ответ:
1)х^4-9=(х²-3)(х²+3)
4х²-9=0; (2х-3)(2х+3)
(63-27)(63+27)/(83-79)(83+79)=36•100/4•162=50/9=5 5/9
4) -(27b^6+1)= -(3b²+1)(9b^4-3b+1)
5) (mn-1)(m²n²+mn+1)
16x²-9-16x²+2x=0
2x=9; x=4,5