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kazloren12ri
@kazloren12ri
August 2022
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Да заряда 15 нКл 40 нКл взаимодействуют с силой 15мкН. Чему равна потенциальная энергия их взаимодействия?
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tana20101997
Verified answer
F=k*q1*q2/R^2
R=sqrt(k*q1*q2/F)=sqrt(9*10^9*15*10^-9*40*10^-9/15*10^-6)=0,6 м
Wp=k*q1*q2/R=9*10^-9*15*10^-9*40*10^-9/0,6=9*10^-6 Дж
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Verified answer
F=k*q1*q2/R^2R=sqrt(k*q1*q2/F)=sqrt(9*10^9*15*10^-9*40*10^-9/15*10^-6)=0,6 м
Wp=k*q1*q2/R=9*10^-9*15*10^-9*40*10^-9/0,6=9*10^-6 Дж