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nizami90
@nizami90
July 2022
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W3MMR
1
. r_1, r1, Klass_10, _123
2
.
y = sqr(a mod b) = sqr(4) = 16.
z = sqrt(trunc(a/b)) + y = sqrt(4) + 16 = 2 + 16 = 18
3
. -5.1 * power(10, 5)
4
. 71000000000
5
.
z := (sqrt(abs((x + y) / 2)))/(sqr(sqr(x+y) + 1.5));
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Answers & Comments
2.
y = sqr(a mod b) = sqr(4) = 16.
z = sqrt(trunc(a/b)) + y = sqrt(4) + 16 = 2 + 16 = 18
3. -5.1 * power(10, 5)
4. 71000000000
5.
z := (sqrt(abs((x + y) / 2)))/(sqr(sqr(x+y) + 1.5));