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haykpes
@haykpes
August 2022
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Дам 70 баллов! Представить квадрат двучлена (11-2n^5)^2 в виде многочлена
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Verified answer
(11-2n^5)^2=
=11^2-2*11*2n^5+(2n^5)^2=
=121-44*n^5+4*n^10
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Verified answer
(11-2n^5)^2==11^2-2*11*2n^5+(2n^5)^2=
=121-44*n^5+4*n^10