September 2021 0 10 Report
Дан прямоугольник ABCD, М ∈ ВС, ∠MAD : ∠АМС = 1 : 3. МС = АВ+ВМ. Площадь Δ АВМ равна 32 см². Найдите площадь прямоугольника ABCD. Помогите, у нас сегодня контрольная работа по геометрии.
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