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kapral6669
@kapral6669
September 2021
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Дана арифметическая прогрессия 6,2,-2,... Найдите сумму семи ее членов, начиная с четвертого и заканчивая десятым.
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NadDer
Verified answer
А1 = 6
d = 2-6 = -4
S3 = (2*6+(-4)*2)/2*3 = 6
S10 = (2*6+(-4)*9)/2*10 = -120
S10-S3 = -120-6 =
-126
10 votes
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Verified answer
А1 = 6d = 2-6 = -4
S3 = (2*6+(-4)*2)/2*3 = 6
S10 = (2*6+(-4)*9)/2*10 = -120
S10-S3 = -120-6 = -126