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Ververa1000
@Ververa1000
August 2022
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Дана арифметическая прогрессия (an), разность которой равна -5,а1=9,2. Найдите а11.
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Donuuut135790
A1=9,2
d=-5
a11=a1+d*(n-1)
a11=9,2-5*(11-1)
a11=9,2-50
a11=-40,8
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Ververa1000
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Donuuut135790
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Answers & Comments
d=-5
a11=a1+d*(n-1)
a11=9,2-5*(11-1)
a11=9,2-50
a11=-40,8