дана функция f(x)= 2x^2 +3x-3 .Найти 1+4f(2x). Created by Madinakarymsakova. matematika-ru

дана функция f(x)= 2x^2 +3x-3 .Найти 1+4f(2x)...

July 2022 1 10 Report

дана функция f(x)= 2x^2 +3x-3 .Найти 1+4f(2x)

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snow99
$f(x) = 2 {x}^{2} + 3x - 3$
$f(2x) = 2 {(2x)}^{2} + 3 \times (2x) - 3 = 8 {x}^{2} + 6x - 3$
$1 + 4f(2x) = 1 + 4 \times (8 {x}^{2} + 6x - 3) = 1 + 32 {x}^{2} + 24x - 12 = 32 {x}^{2} + 24x - 11$

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