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Snezhanochka
@Snezhanochka
July 2022
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Дана функция f(x)=x^2-4x+1 При каком x значение функции равно 4.
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nafanya2014
Verified answer
Надо составить уравнение
f(x)=4
или
х²-4х+1=4
х²-4х+1-4=0
х²-4х-3=0
D=(-4)²-4·(-3)=16+12=28
√D=√28=√(4·7)=2·√7
x₁ =(4-2√7)/2=2-√7 или x₂=(4+2√7)/2=2+√7
Ответ. при x =2-√7 или при x=2+√7
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Answers & Comments
Verified answer
Надо составить уравнениеf(x)=4
или
х²-4х+1=4
х²-4х+1-4=0
х²-4х-3=0
D=(-4)²-4·(-3)=16+12=28
√D=√28=√(4·7)=2·√7
x₁ =(4-2√7)/2=2-√7 или x₂=(4+2√7)/2=2+√7
Ответ. при x =2-√7 или при x=2+√7