дана функция у= - х^2+8х-12
как найти вершину?
О(n; m)
n = -b/ 2*a = -8/ 2*(-1) = 4
m= y(n) = -4^2 +8*4-12 = -16+32-12 = -28+32= 4
O(4;4)
xo=-b/2a=-8/-2=4
yo=-4^2+8*4-12=-16+32-12=4
(4.4)
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Answers & Comments
О(n; m)
n = -b/ 2*a = -8/ 2*(-1) = 4
m= y(n) = -4^2 +8*4-12 = -16+32-12 = -28+32= 4
O(4;4)
xo=-b/2a=-8/-2=4
yo=-4^2+8*4-12=-16+32-12=4
(4.4)