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@gjjgljfgj54
August 2022
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Дана функция y=f(x), где f(х) =2х^2 - 3х + 8 найдите f (-4)
2) А(;4 64) В(5; --80)
Какой из днанных точек принадлежит графику функций у=-4х^2
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лидия69
Verified answer
Y=f (x)
f (-4)=2(-4)^2-3 (-4)+8=2×16+12+8 =32+20=52
y=-4x^2
a (4;64)
64=-4×4^2
64=-4×16
64=-64 не принад.
в (5;-80)
-80=-4×5^2
-80=-4×25
-80=-100 не принадлеж.
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Answers & Comments
Verified answer
Y=f (x)f (-4)=2(-4)^2-3 (-4)+8=2×16+12+8 =32+20=52
y=-4x^2
a (4;64)
64=-4×4^2
64=-4×16
64=-64 не принад.
в (5;-80)
-80=-4×5^2
-80=-4×25
-80=-100 не принадлеж.