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teisan
@teisan
December 2021
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Дана геометрическая прогрессия 3;6;12;.... .Найдите S(6) S(n)
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mmb1
Verified answer
3;6;12
b1=3
q=6/3=2
s6=b1(q^6-1)/(q-1)=3*(2^6-1)/(2-1)=3*63=189
sn=b1(q^n-1)/(q-1)=3(2^n-1)
;.... .Найдите S(6) S(n)
6 votes
Thanks 5
danark5
S6=
3*(1-2^6)
= 189
1-2
3 votes
Thanks 2
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Answers & Comments
Verified answer
3;6;12b1=3
q=6/3=2
s6=b1(q^6-1)/(q-1)=3*(2^6-1)/(2-1)=3*63=189
sn=b1(q^n-1)/(q-1)=3(2^n-1)
;.... .Найдите S(6) S(n)
S6=3*(1-2^6) = 189
1-2