Home
О нас
Products
Services
Регистрация
Войти
Поиск
voronovaoksana3
@voronovaoksana3
July 2022
2
5
Report
Дана квадратичная функция f(x)=x²+2. Найдите значения:
1) f(4)
2) f(-3)
Помогите пожалуйста!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
ias13
F(4) = 4^2 + 2 = 16 + 2 = 18
f(-3) = (-3)^2 + 2 = 9 + 2 = 11
2 votes
Thanks 3
voffczlnick
F(4) = 18
f(-3) = 11
F(-1/2) = 2,25
F(-0.2) = 2,04
1 votes
Thanks 0
×
Report "Дана квадратичная функция f(x)=x²+2. Найдите значения: 1) f(4) 2) f(-3) Помогите..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
f(-3) = (-3)^2 + 2 = 9 + 2 = 11
f(-3) = 11
F(-1/2) = 2,25
F(-0.2) = 2,04