дана трапеция
1-я основа + 2-я основа = k
1-ое бедро + 2-ое бедро = q
S = ?
S=(a+b)/2*H=k*H/2=
2=k-1
H=(k-1)^2+(q-2)^2
S=k(k-1)^2+(q-2)^2/2
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Verified answer
S=(a+b)/2*H=k*H/2=
2=k-1
H=(k-1)^2+(q-2)^2
S=k(k-1)^2+(q-2)^2/2