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krasvetaficbook
@krasvetaficbook
August 2022
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Дано: 2sinА - 2cosА = 1
Найдите: sinАcosА = ?
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kirichekov
Verified answer
2sinα-2scosα=1, 2*(sinα-cosα)=1
sinα-cosα=1/2
(sinα-cosα)²=(1/2)²
sin²α-2sinαcosα+cos²α=1/4
(sin²α+cos²α)-2sinαcosα=1/4
2sinαcosα=1-1/4, 2sinαcosα=3/4 | : 2
sinαcosα=3/8
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Answers & Comments
Verified answer
2sinα-2scosα=1, 2*(sinα-cosα)=1sinα-cosα=1/2
(sinα-cosα)²=(1/2)²
sin²α-2sinαcosα+cos²α=1/4
(sin²α+cos²α)-2sinαcosα=1/4
2sinαcosα=1-1/4, 2sinαcosα=3/4 | : 2
sinαcosα=3/8