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stephennikirin
@stephennikirin
July 2022
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дано а=20 угол Б =60° угол А=75°
найти б, с ,угол с
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anassstass
По теореме синусов:
a/A = b/B = c/C
a/A = b/B = 20/sin75 = b/sin60 = 20/0,9659 = b/0,8660, отсюда b = 20*0,8660/0,9659 = 17,9 ~ 18 см
Угол С = 180° - (75°+60°) = 45°
a/A = c/C
20/0,9659 = c/sin45 = 20/0,9659 = c/0,7071, отсюда с = 20*0,7071/0,9659 = 14,6 ~ 15 см
Ответ: 45°; 18 см; 15 см.
10 votes
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Answers & Comments
a/A = b/B = c/C
a/A = b/B = 20/sin75 = b/sin60 = 20/0,9659 = b/0,8660, отсюда b = 20*0,8660/0,9659 = 17,9 ~ 18 см
Угол С = 180° - (75°+60°) = 45°
a/A = c/C
20/0,9659 = c/sin45 = 20/0,9659 = c/0,7071, отсюда с = 20*0,7071/0,9659 = 14,6 ~ 15 см
Ответ: 45°; 18 см; 15 см.