Дано: АВСD – параллелограмм, ВН – высота
Доказать: SABCD = AD · BH
Доказательство:
1) CК ┴ AD
2) Рассмотрим Δ АНВ и Δ DKC – _________________________
AB = CD, как __________________________________ ____
ےВАР = ےCDK, как ____________________________ _____
Δ АНВ = Δ DKC по ______________________________________.
3) SABCD = S_________ + S__________
SHBCK = S_________ + S__________
SHBCK = _________________
SABCD = _________________
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