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Svetatakesheva
@Svetatakesheva
July 2022
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Дано АВСД-прямоугольник, а=? см, в=7 см,Р(периметр)=34 см.Найти S(площадь)-прямоугольника?
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Aryiona
S=a×b
P=2×(a+b)
2×(a+7)=32
a+7=32÷2
a+7=16
a=16-7
a=9
S=7×9=63
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Answers & Comments
P=2×(a+b)
2×(a+7)=32
a+7=32÷2
a+7=16
a=16-7
a=9
S=7×9=63