Объяснение:
Mr(BaCl2) =137+35,5*2=208
W(Ba) =Ar(Ba) /Mr(BaCl2) *100% =137/208 *100%=65,9 %
W(Cl)=2*Ar(Cl) /Mr(BaCl2) *100%=71/208 *100%=34,1 %
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Объяснение:
Mr(BaCl2) =137+35,5*2=208
W(Ba) =Ar(Ba) /Mr(BaCl2) *100% =137/208 *100%=65,9 %
W(Cl)=2*Ar(Cl) /Mr(BaCl2) *100%=71/208 *100%=34,1 %