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X1337
@X1337
July 2022
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Дано: ΔACB,CA=CB. Основание треугольника на 11 дм меньше боковой стороны. Периметр треугольника ACB равен 121 дм. Вычисли стороны треугольника. BA= CB= CA=
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Vilmar
AC=AB
AB+11=AC
2AC+AB=121
2(AB+11)+AB=121
2AB+22+AB=121
3AB=99
AB=33
AC=33+11=44
AC=44 дм CB=44 дм AB=33 дм
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Answers & Comments
AB+11=AC
2AC+AB=121
2(AB+11)+AB=121
2AB+22+AB=121
3AB=99
AB=33
AC=33+11=44
AC=44 дм CB=44 дм AB=33 дм