Дано: m(C6H6)=12г.
ω(C6H5NO2)=80%
C6H6+HNO3=C6H5NO2+H2O
Найти:m(C6H5NO2)
ω(C6H5NO2)=80%
C6H6+HNO3=C6H5NO2+H2O
Найти:m(C6H5NO2)
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78 123
находим массуC5H5NO2 = 12г*123г/78 = 18,9г получили 100% -ую
18,9-----100%
х ---------80% х =15,1гC5H5NO2