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Yulenka26
@Yulenka26
August 2022
1
8
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Дано:
CxHy
w(C)=51.89%
w(Cl)=38.38%
остальное - H
D(H)=46.25
выведите формулу!
помогите пожалуйста
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НервныеНервы
Mr(по H2)=2*46.25=92.5 г/моль
n(C)=0.5189*92.5/12=4 моль
n(Cl)=0.3838*92.5/35.5=1 моль
n(H)=0.0973*92.5/1=9 моль
C4ClH9
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Answers & Comments
n(C)=0.5189*92.5/12=4 моль
n(Cl)=0.3838*92.5/35.5=1 моль
n(H)=0.0973*92.5/1=9 моль
C4ClH9