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karishaa11
@karishaa11
August 2022
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Даны четыре последовательных нечетных числа. Докажите, что произведение крайних чисел меньше произведения средних на 8
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MarinaManskova
2n+1, 2n+3, 2n+5, 2n+7;
B=(2n+1)*(2n+7)=4n²+2n+14n+7=4n²+16n+7;
A=(2n+3)*(2n+5)=4n²+6n+10n+15=4n²+16n+15;
A-B=(4n²+16n+15)-(4n²+16+7)=15-7=8
5 votes
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