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tekkenknigin
@tekkenknigin
July 2022
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Даны четыре точки А (0; 1; -1), Б (1; -1; 2), С (3; 1; 0), D (2; -3; 1). Найдите косинус угла ф между векторами ¯(АВ и CD.)
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au456
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Вектора
АВ(1;-2;3) длина √(1+4+9)=√14
CD(-1;-4;1) длина √(1+16+1)=√18
соs ф= | АВ * CD | / |AB | / | CD | =
(-1+8+3)/√14/√18=5/√63
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ВектораАВ(1;-2;3) длина √(1+4+9)=√14
CD(-1;-4;1) длина √(1+16+1)=√18
соs ф= | АВ * CD | / |AB | / | CD | =
(-1+8+3)/√14/√18=5/√63