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AnastasiC
@AnastasiC
August 2022
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Даны числа tg240, sin120, cos150, ctg225 (градусов).
Найдите произведение большего из них на наименьшее.
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ЧемМогуПомогу
tg240=tg(180+60)=tg60=sqrt3,
sin120=sin(90+30)=cos30=sqrt3/2,
cos150=cos(180-30)=-cos30=
sqrt3/2,
ctg225
=ctg(180+45)=ctg45=1
sqrt3*
sqrt3/2=3/2=1,5
Ответ:1,5
3 votes
Thanks 5
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Answers & Comments
sin120=sin(90+30)=cos30=sqrt3/2,
cos150=cos(180-30)=-cos30=sqrt3/2,
ctg225=ctg(180+45)=ctg45=1
sqrt3*sqrt3/2=3/2=1,5
Ответ:1,5