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Student444
@Student444
July 2022
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Даны две последовательности An=3n-4 и Bn=-n^2. При каких значениях n выполняется неравенство An≥Bn
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sedinalana
3n-4≥-n²
n²+3n-4≥0
n1=n2=-3 U n1*n2=-4
n1=-4 U n2=1 U n∈N
n≥1
n∈[1;∞)
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Student444
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Answers & Comments
n²+3n-4≥0
n1=n2=-3 U n1*n2=-4
n1=-4 U n2=1 U n∈N
n≥1
n∈[1;∞)