Даны точки а(-5;2), B(5;2),С(-3,6) разложите вектор BO (О-начало координат) по векторам АВ и СВ. Created by silonte. matematika-ru

Task/26667396-------------------Даны точки A(-5;2), B(5;2), С(-3,6)разложите вектор BO (О-начало координат) по векторам AB и СВ .-----------------------BO( 0 -5 ; 0 -2) , т.е. BO( -5 ; - 2) .AB( 5 -(-5) ; 2 -2) , т.е. AB(10 ; 0) .AC( -3 -(-5) ; 6 -2) , т.е. AC(2 ; 4) .BO =m*AB +n*AC ; * * * m*AB +n*AC = BO * * * {10m +2n = - 5 ; { 10m +2*(-1/2) = -5 ; { m = -2/5 ;{0*m +4n = - 2. ⇔ { n = - 1/2 . ⇔ { n= - 1/2.ответ: BO = (-2/5)*AB +(-1/2)*AC . * * * BO = -0,4*AB - 0,5*AC . * * *Новые вопросы в МатематикаПомогите пожалуйста решить вот такое задание. Задание номер 8:Укажите естественную область определения : примеры на фото4. Родина Ковальчуків за листопад 2016 року отримала від «Укртелекому рахунок у розмірі 48 грн. Скільки коштів буде перераховано як ПДВ після сплати р…одиною цього рахунку?Во время сеанса было заполнено 5/6 зала. Сколько мест в кинозале, если свободными осталось 60 мест?ПОМОГИТЕ ДАМ ЗА ЕТО 20 БАЛЛОВ5. З'єднай лінією виміри прямокутника і його пери- метр. 10 мi 15 м. 10мi5 м. 12 см і 13 см • 16 • 50 см • 50 м • 30 м ПОМОГИТЕ СРОЧНО ПОЖАЛУЙСТА 151. Напишіть три такі пари складених чисел, щобу кожній парі числа були взаемно простими.НАДО СРОЧНОПОМОГИТЕ СРОЧНО ДАМ 15 БАЛЛОВ400: x = 20. • x = 10 5. З'єднай лiнiєю виміри прямокутника і його периметр:1)10м і 15м 1)50см2)10м і 5м 2)50м3)12см і…13 см 3)30м Помогите пожалуйста разобраться :Нужно решить задание 5: Имеет ли смысл алгебраическое выражение:а).(16а-3)-2-4---------------- ;15б). 21а-14…--------------;9-25+162. Найдите значение выражения, используя распределительное свойство умножения:1) (1 14/17 - 1 1/34)*342) 8 3/17*5 1/4+3 14/17 *5 1/4ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Даны точки а(-5;2), B(5;2),С(-3,6) разложите вектор BO (О-начало координат) по в...

silonte @silonte

August 2022 1 57 Report

Даны точки а(-5;2), B(5;2),С(-3,6)
разложите вектор BO (О-начало координат) по векторам АВ и СВ

Answers & Comments

oganesbagoyan

Verified answer

Task/26667396
-------------------
Даны точки A(-5;2), B(5;2), С(-3,6)
разложите вектор BO (О-начало координат) по векторам AB и СВ .
-----------------------
BO( 0 -5 ; 0 -2) , т.е. BO( -5 ; - 2) .
AB( 5 -(-5) ; 2 -2) , т.е. AB(10 ; 0) .
AC( -3 -(-5) ; 6 -2) , т.е. AC(2 ; 4) .

BO =m*AB +n*AC ; * * *  m*AB +n*AC = BO * * *
{10m +2n = - 5 ; { 10m +2*(-1/2) = -5 ; { m = -2/5 ;
{0*m +4n = - 2.  ⇔ {  n = - 1/2 .   ⇔ { n= - 1/2.

ответ:  BO = (-2/5)*AB +(-1/2)*AC . * * * BO = -0,4*AB - 0,5*AC . * * *