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girlwithgunonlsd
@girlwithgunonlsd
August 2022
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Даны точки А(1;5;-2) В(2;0;0) С(3;0;-4). Найдите косинус угла между векторами АВ и АС.
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dnepr1
Verified answer
Вектор АВ: (2-1=1; 0-5=-5; 0-(-2)=2) = (1;-5;2).
Вектор АС: (3-1=2; 0-5=-5; -4-(-2)=-2) = (2;-5;-2).
cosα = |2+25-4| / (√(1+25+4)*√(4+25+4) = 23/(√30*√33) = 23/(3√110) ≈
0,730988.
Угол равен 0,751028радиан или
43,03072градуса.
2 votes
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Answers & Comments
Verified answer
Вектор АВ: (2-1=1; 0-5=-5; 0-(-2)=2) = (1;-5;2).Вектор АС: (3-1=2; 0-5=-5; -4-(-2)=-2) = (2;-5;-2).
cosα = |2+25-4| / (√(1+25+4)*√(4+25+4) = 23/(√30*√33) = 23/(3√110) ≈ 0,730988.
Угол равен 0,751028радиан или43,03072градуса.