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timmylol
@timmylol
July 2022
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Даны точки A(2;-3), B(-1;2), C(k;1). Найдите вектор AB×(вектор AC - BC) + вектор BC×(вектор CB - AB + AC)
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sedinalana
AB{-3;5}
AC{k-2;4}
BC{k+1;-1}
AC-BC{-3;5}
CB-AB+AC{-k-1+3+k-2;1-5+4}={0;0}
AB*(AC-BC)+BC*(CB-AB+AC)=-3*(-3)5*5+(k+1)*0+(-1)*0=9+25=34
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Answers & Comments
AC{k-2;4}
BC{k+1;-1}
AC-BC{-3;5}
CB-AB+AC{-k-1+3+k-2;1-5+4}={0;0}
AB*(AC-BC)+BC*(CB-AB+AC)=-3*(-3)5*5+(k+1)*0+(-1)*0=9+25=34