Даны три множества:
X= {a,s,z,d},
Y= {z,d,e,f},
Z= {z,p,q}.
(X∩Y)∪Z={
,
,
,d}
X= {a,s,z,d},
Y= {z,d,e,f},
Z= {z,p,q}.
(X∩Y)∪Z={
,
,
,d}
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Объяснение:
(X∩Y)∪Z={z, d}∪{z, p, q}={z, d, p, q}