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mick85
@mick85
August 2022
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Даны три точки A(0;4;1);B(1;3;0) И C(0;2;5).Найдите длину вектора m=AC-CB
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dnepr1
Verified answer
Длина вектора m=AC-CB = АС+ВС.
Вектор ВС = (0-1=-1;2-3=-1;5-0=5) = (-1;-1; 5).
Вектор AС = (0-0=0;2-4=-2;5-1=4) = (0;-2; 4) сложим:
-----------------
-1; -3; 9.
Длина такого вектора равна: √((-1)²+(-3)²+9²) = √(1+9+81) = √91 ≈
9,539392.
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Answers & Comments
Verified answer
Длина вектора m=AC-CB = АС+ВС.Вектор ВС = (0-1=-1;2-3=-1;5-0=5) = (-1;-1; 5).
Вектор AС = (0-0=0;2-4=-2;5-1=4) = (0;-2; 4) сложим:
-----------------
-1; -3; 9.
Длина такого вектора равна: √((-1)²+(-3)²+9²) = √(1+9+81) = √91 ≈ 9,539392.