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Marischka2599
@Marischka2599
July 2022
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даны вектора а(1;-2;0) в (2;1;-3) найти длину вектора а и в
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sedinalana
Verified answer
|a|=√1²+(-2)²+0²=√(1+4+0)=√5
|b|=√2²+1²+(-3)²=√(4+1+9)=√14
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Verified answer
|a|=√1²+(-2)²+0²=√(1+4+0)=√5|b|=√2²+1²+(-3)²=√(4+1+9)=√14