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alisasafronowa
@alisasafronowa
July 2022
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Даны векторы a(-2;1)b(3;4). Найти 5а^2-3а*b-2b^2
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nelle987
Verified answer
A^2 = (-2)^2 + 1^2 = 4 + 1 = 5
a*b = (-2) * 3 + 1 * 4 = -6 + 4 = -2
b^2 = 3^2 + 4^2 = 9 + 16 = 25
5a^2 - 3ab - 2b^2 = 5 * 5 - 3 * (-2) - 2 * 25 = 25 + 6 - 50 = -19
Для справки правила скалярного произведения векторов:
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Answers & Comments
Verified answer
A^2 = (-2)^2 + 1^2 = 4 + 1 = 5a*b = (-2) * 3 + 1 * 4 = -6 + 4 = -2
b^2 = 3^2 + 4^2 = 9 + 16 = 25
5a^2 - 3ab - 2b^2 = 5 * 5 - 3 * (-2) - 2 * 25 = 25 + 6 - 50 = -19
Для справки правила скалярного произведения векторов: