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baras2001
@baras2001
August 2022
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Даны векторы а(2;3) и b(-1;0). Найдите координаты вектора. 1)2a +b 2)a -3b 3)2b -a 4)-2b -4a
на верху a и b есть стрелка 8-КЛАСС
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Lesben
A(2,3),b(-1,0)
1)2a+b = 2.(2,3)+(-1,0)=(4,6)+(-1,0)=(3,6)
2)a-3b=(2,3)-3.(-1,0)=(2,3)-(-3,0)=(5,3)
3)2b-a=2.(-1,0)-(2,3)=(-2,0)-(2,3)=(-4,-3)
4)-2b-4a=-2(-1,0)-4(2,3)=(2,0)-(8,12)=(-6,-12)
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Answers & Comments
1)2a+b = 2.(2,3)+(-1,0)=(4,6)+(-1,0)=(3,6)
2)a-3b=(2,3)-3.(-1,0)=(2,3)-(-3,0)=(5,3)
3)2b-a=2.(-1,0)-(2,3)=(-2,0)-(2,3)=(-4,-3)
4)-2b-4a=-2(-1,0)-4(2,3)=(2,0)-(8,12)=(-6,-12)