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alla3456
@alla3456
August 2022
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даны векторы a=2i-j+k и b=3i+2k. Найти модуль вектора a-2b
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vasilek126
Verified answer
A-2b=2i-j+k-6i-4k=-4i-j-3k
|a-2b|=√(16+1+9)=√26
a=2i+3j+3k; b=i+2j-k;
a+b=3i+5j-3k; 2a-b=4i+6j+6k-i-2j+k=3i+4j+7k;
(a+b)•(2a-b)=3•3+5•4-3•7=9+20-21=8
ответ:8
8 votes
Thanks 13
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Answers & Comments
Verified answer
A-2b=2i-j+k-6i-4k=-4i-j-3k|a-2b|=√(16+1+9)=√26
a=2i+3j+3k; b=i+2j-k;
a+b=3i+5j-3k; 2a-b=4i+6j+6k-i-2j+k=3i+4j+7k;
(a+b)•(2a-b)=3•3+5•4-3•7=9+20-21=8
ответ:8