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nightpatrol555
@nightpatrol555
July 2022
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Даны вершины треугольника A(7;-8;2) , B(10:-8:-1) , С(11;-4;2).Найдите величину угла BAC этого треугольника.
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sedinalana
Verified answer
AB=√[(10-7)²+(-8+8)²=(1-2)²]=√(9+0+1)=√10
AC=√[(11-7)²(-4+8)²+(2-2)²]=√(16+16+0)=√32=4√2
BC=√[(11-10)²+(-4+8)²+(2-1)²]=√(1+16+1)=√18=3√2
cosBAC=(AB²+AC²-BC²)/(2*AB*AC)=(10+32-18)/(2*√10*4√2)=
=24/(8√20)=3/√20≈0,6708
<BAC≈48
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Answers & Comments
Verified answer
AB=√[(10-7)²+(-8+8)²=(1-2)²]=√(9+0+1)=√10AC=√[(11-7)²(-4+8)²+(2-2)²]=√(16+16+0)=√32=4√2
BC=√[(11-10)²+(-4+8)²+(2-1)²]=√(1+16+1)=√18=3√2
cosBAC=(AB²+AC²-BC²)/(2*AB*AC)=(10+32-18)/(2*√10*4√2)=
=24/(8√20)=3/√20≈0,6708
<BAC≈48