A=(1/3)^(-1)+√16-=3^1+4-2=8
B=∛64-+()^0=∛(2^6)-2+1= 2^2-2+1=4-2+1=3
8>2*3
A>2B
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A=(1/3)^(-1)+√16-
=3^1+4-2=8
B=∛64-
+(
)^0=∛(2^6)-2+1= 2^2-2+1=4-2+1=3
8>2*3
A>2B