Ответ:
64z³-27y³=(4z-3y)(16z²+12yz+9y²) - формула куба
[tex]\displaystyle 64x^3-27y^3=4^3z^3-3^3y^3=(4z)^3-(3y)^3=(4z-3y)((4z)^2+4z*3y+(3y)^2)=(4z-3y)(16z^2+12yz+9y^2)[/tex]
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Ответ:
64z³-27y³=(4z-3y)(16z²+12yz+9y²) - формула куба
[tex]\displaystyle 64x^3-27y^3=4^3z^3-3^3y^3=(4z)^3-(3y)^3=(4z-3y)((4z)^2+4z*3y+(3y)^2)=(4z-3y)(16z^2+12yz+9y^2)[/tex]