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Nemuverus
@Nemuverus
August 2022
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Даю 100 баллов, решить 1 на выбор
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армения20171
Verified answer
1)(1+у)dx-(x-1)dy=0
dx/(x-1)-dy/(1+y)=0
dx/(x-1)=dy/(1+y)
d(x-1)/(x-1)=d(y+1)/(y+1)
интегралd(x-1)/(x-1)=
интегралd(y+1)/(y+1)
ln(y+1)=ln(x-1)+C
(y+1)/(x-1)=C
y+1=(x-1)*C
y=x•C-(C+1)
2 votes
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Answers & Comments
Verified answer
1)(1+у)dx-(x-1)dy=0dx/(x-1)-dy/(1+y)=0
dx/(x-1)=dy/(1+y)
d(x-1)/(x-1)=d(y+1)/(y+1)
интегралd(x-1)/(x-1)=
интегралd(y+1)/(y+1)
ln(y+1)=ln(x-1)+C
(y+1)/(x-1)=C
y+1=(x-1)*C
y=x•C-(C+1)