<B=180-<A-<C=180-85-81=14°
AC/sinB=CB/sinA=AB/sinC
480/sin14=CB/sin85=AB/sin81
CB=490*sin85/sin14≈2033.9
ΔBCD-прямоугольный
BD=BC*sin<C≈2033.9*0.987≈2008.86 м
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<B=180-<A-<C=180-85-81=14°
AC/sinB=CB/sinA=AB/sinC
480/sin14=CB/sin85=AB/sin81
CB=490*sin85/sin14≈2033.9
ΔBCD-прямоугольный
BD=BC*sin<C≈2033.9*0.987≈2008.86 м