Ответ:

a) f(x)= 0.25·x²-2·x+2

b)f(x)=Mod(-x/4-1.75)

Объяснение:

a) f(2x+1)=x²-3x

2x+1=z => 2x=z-1 => x= (z-1)/2 ; x²=(z-1)²/4

=> f(z)= (z-1)²/4-3(z-1)/2 = (z²-2z+1)/4 - (6z-6)/4

=>f(z)= (z²-2z-6z+1+7)/4= (z²-8z+8)/4 = 0.25·z²-2·z+2

=> f(x)= 0.25·x²-2·x+2

b) f(1-4x)=Mod(x-2)

1-4x=z => 4x=1-z => x= (1-z)/4

=> f(z)= Mod(1/4-z/4-2) = Mod (-z/4 -1.75)

=>f(x)=Mod(-x/4-1.75)