Даю 18 балов , решите пожалуйста номера 13,14,15,16 .. Created by alena5533. algebra-ru

13) = 3*2^(-1/2) + 3*10*2^(-1/2)-3*2²*2^(-3/2) = = (33 / √2) - 3√2 = 19.09188.14) = 15.65248 15) 16) 0,5√72 + (1/4)√128 - √98 = -2.82843.

Даю 18 балов , решите пожалуйста номера 13,14,15,16...

alena5533 @alena5533

July 2022 1 2 Report

Даю 18 балов , решите пожалуйста номера 13,14,15,16 .

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dnepr1

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13) $\frac{3}{ \sqrt{2} } + \frac{3}{2} * \sqrt{200} -12* \sqrt{ \frac{1}{8} } =$
= 3*2^(-1/2) + 3*10*2^(-1/2)-3*2²*2^(-3/2) =
= (33 / √2) - 3√2 = 19.09188.
14) $\frac{200}{ \sqrt{5} } -2,5 \sqrt{180} -30 \sqrt{ \frac{9}{5} } =$
= $\frac{200-15*5-90}{ \sqrt{5} } = \frac{35}{ \sqrt{5} } =7 \sqrt{5} =$ 15.65248
15) $1,5 \sqrt{ \frac{2}{3} } +2 \sqrt{1,5} -3 \sqrt{ \frac{1}{6} } =$
$= \frac{3}{2} * \frac{ \sqrt{2} }{ \sqrt{3} } + \frac{2* \sqrt{3} }{ \sqrt{2} } - \frac{3*1}{ \sqrt{6} } =$
$= \frac{3+2*3-3}{ \sqrt{6} } = \frac{6}{ \sqrt{6} } = \sqrt{6} .$
16) 0,5√72 + (1/4)√128 - √98 = $\frac{1}{2} *6 \sqrt{2} } + \frac{1}{4} *8 \sqrt{2} -7 \sqrt{2} =-2 \sqrt{2} =$ -2.82843.

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