Home
О нас
Products
Services
Регистрация
Войти
Поиск
ГОШИК123
@ГОШИК123
July 2022
2
13
Report
Даю 20 баллов, помогите решить систему уравнений
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
rubilovalex
X=2y+1. подставляем во 2 уравнение: (2y+1)*y+y=12; 2y^2+y+y-12=0; 2y^2+2y-12=0; D=2^2-4*2*(-12)=4+96=100; y1=(-2-10)/4, y2=(-2+10)/4. y1= -3, y2=2. x1=2*(-3)+1= -6+1= -5. x2=2*2+1=4=1=5. Ответ( -5: -3), (5:2).
2 votes
Thanks 1
ГОШИК123
Спасибо большое
ПрофиЗнания
X=1+2y
(1+2y)y+y=12
y+2y²+y-12=0
2y²+2y-12=0 :2
y²+y-6=0
D=1-4*(-6)*1=1+24=25=5²
y1=-1+5/2=4/2=2
y2=-1-5/2=-6/2=-3
x1=1+2*2=1+4=5
x2=1+2*(-3)=1-6=-5
1 votes
Thanks 1
×
Report "Даю 20 баллов, помогите решить систему уравнений..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(1+2y)y+y=12
y+2y²+y-12=0
2y²+2y-12=0 :2
y²+y-6=0
D=1-4*(-6)*1=1+24=25=5²
y1=-1+5/2=4/2=2
y2=-1-5/2=-6/2=-3
x1=1+2*2=1+4=5
x2=1+2*(-3)=1-6=-5