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airatm
@airatm
July 2022
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Даю 20 баллов!Помогите решить неравенство (3x-2)^2-4x (2x+3)》0
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sedinalana
Verified answer
(3x-2)²-4x(2x+3)≥0
9x²-12x+4-8x²-12x≥0
x²-24x+4≥0
D=576-16=560
√D=4√35
x1=(24-4√35)/2=12-2√35 U x2=12+2√35
+ _ +
-----------------[12-2√35]-----------[12+2√35]----------------
x∈(-∞;12-2√35] U [12+2√35;∞)
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Answers & Comments
Verified answer
(3x-2)²-4x(2x+3)≥09x²-12x+4-8x²-12x≥0
x²-24x+4≥0
D=576-16=560
√D=4√35
x1=(24-4√35)/2=12-2√35 U x2=12+2√35
+ _ +
-----------------[12-2√35]-----------[12+2√35]----------------
x∈(-∞;12-2√35] U [12+2√35;∞)