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ivan11886
@ivan11886
June 2022
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ДАЮ 20 БАЛЛОВ.ТРИГОНОМЕТРИЧЕСКИЕ ВЫРАЖЕНИЯ.
1)2+3tg^2x, если cos^2x= 0,6
2)tg^2альфа , если 45sin^2альфа +11cos^2альфа =20
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kirichekov
Verified answer
1. 2+3*tg²x=?, cos²x=0,6
1+tg²x=1/cos²x
1+tg²x=1/0,6². 1+tg²x=1:(36/100). 1+tg²x=100/36. tg²x=100/36-1
tg²x=64/36
2+3*tg²x=2+3*(64/36)=2+16/3=
22/3
2. tg²α-? 45sin²α+11cosα=20
34sin²α+11sin²α +11cos²α=20, 34sin²α+11*(sin²α+cos²α)=20, 34sin²α+11=20
sin²α=9/34
sin²α+cos²α=1
9/34+cos²α=1, cos²α=1-9/34, cos²α=25/34
1+tg²α=1:(25/34), tg²α=34/25-1
tg²α=9/25
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Answers & Comments
Verified answer
1. 2+3*tg²x=?, cos²x=0,61+tg²x=1/cos²x
1+tg²x=1/0,6². 1+tg²x=1:(36/100). 1+tg²x=100/36. tg²x=100/36-1
tg²x=64/36
2+3*tg²x=2+3*(64/36)=2+16/3=22/3
2. tg²α-? 45sin²α+11cosα=20
34sin²α+11sin²α +11cos²α=20, 34sin²α+11*(sin²α+cos²α)=20, 34sin²α+11=20
sin²α=9/34
sin²α+cos²α=1
9/34+cos²α=1, cos²α=1-9/34, cos²α=25/34
1+tg²α=1:(25/34), tg²α=34/25-1
tg²α=9/25