даю 30 баллов!!!!!!!!. Created by 3613295. algebra-ru

даю 30 баллов!!!!!!!!...

3613295 @3613295

August 2021 1 7 Report

даю 30 баллов!!!!!!!!

Answers & Comments

aiymgul84

Ответ:

$\frac{y + x}{xy} \times \frac{2xy}{(x - y)(x + y)} = \frac{2}{x - y}$

$\frac{y(y + 3)}{ {(y - 3)}^{2} } \div \frac{3y - 9 + {y }^{2} + 9 + 3y + 9 }{(y - 3)(y + 3)} = \frac{y(y + 3)}{ {(y - 3)}^{2} } \times \frac{(y - 3)(y + 3)}{ {y}^{2} + 6y + 9 } = \frac{y( {y + 3)}^{2} }{(y - 3)(y + 3 {)}^{2} } = \frac{y}{y - 3}$

$\frac{3 {y}^{2} - 12y - 6y}{(y - 4) {}^{2} } \times \frac{(y - 4)(y + 4)}{24 {y}^{2} + 96y - y + 6 } = \frac{3 {y}^{2} - 18y}{ {(y - 4)}^{2} } \times \frac{(y - 4)(y + 4)}{24 {y}^{2} + 95y + 6 } = \frac{3y(y - 9)(y + 4)}{(y - 4)(24 {y}^{2} + 95y + 6) }$

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