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Verified answer

Ответ:

n-1; n; n+1; n+2;

n²-(n-1)²+(n+2)²-(n+1)²=18

((n-(n-1)) (n+n-1)+((n+2-(n+1)) (n+2+n+1)=18

1(2n-1)+1) (2n+3)=18

2n-1+2n+3=18

4n=16

n=4

ответ:3,4,5,6