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mixmix2002
@mixmix2002
March 2022
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Даю 50 баллов Только точные решения решается оценка
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Alexei78
Verified answer
Дано
V(H2) = 150 L
m(Br2) = 65 g
η (HBr) = 75 %
-------------------
Vпракт(HBr)-?
n(H2) = V(H2) / Vm = 150/22.4 = 6.7 mol
M(Br2) = 160 g/mol
n(Br2) = m/M = 65 / 160 = 0,4 mol
n(H2) > n(Br2)
H2+Br2-->2HBr
n(Br2) = 2n(HBr), n(HBr) = 2*0.4 = 0.8 mol
V теор (HBr) = n*Vm = 0.8*22.4 = 17.92 L
V практ (HBr) = V(HBr) * η / 100% = 17.92 * 75% / 100% = 13.44 л
ответ 13.44 л
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Answers & Comments
Verified answer
ДаноV(H2) = 150 L
m(Br2) = 65 g
η (HBr) = 75 %
-------------------
Vпракт(HBr)-?
n(H2) = V(H2) / Vm = 150/22.4 = 6.7 mol
M(Br2) = 160 g/mol
n(Br2) = m/M = 65 / 160 = 0,4 mol
n(H2) > n(Br2)
H2+Br2-->2HBr
n(Br2) = 2n(HBr), n(HBr) = 2*0.4 = 0.8 mol
V теор (HBr) = n*Vm = 0.8*22.4 = 17.92 L
V практ (HBr) = V(HBr) * η / 100% = 17.92 * 75% / 100% = 13.44 л
ответ 13.44 л